(3)/(X+9)-6/(X+5)=(-12)/(x^2+14x+45)

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Solution for (3)/(X+9)-6/(X+5)=(-12)/(x^2+14x+45) equation: 


D( x )

X+5 = 0

X+9 = 0

x^2+14*x+45 = 0

X+5 = 0

X+5 = 0

X+5 = 0

x naleu017Cy do R

X+9 = 0

X+9 = 0

X+9 = 0

x naleu017Cy do R

x^2+14*x+45 = 0

x^2+14*x+45 = 0

x^2+14*x+45 = 0

DELTA = 14^2-(1*4*45)

DELTA = 16

DELTA > 0

x = (16^(1/2)-14)/(1*2) or x = (-16^(1/2)-14)/(1*2)

x = -5 or x = -9

x belongs to the empty set

3/(X+9)-(6/(X+5)) = -12/(x^2+14*x+45)

x belongs to the empty set

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